Exploring Isotopes & Average Atomic Mass

The guiding question of this lab: What is the atomic mass of beanium?
What I did during these lab was first i did this graph:

Data
Type of Bean Total number Total  Mass Average Mass Percent
Limium 5 7.0g 1.4g 10%
Kidneyum 15 8.0g 0.53g 30%
Peagen   30 6.5g .22g 60%

Then i got the mass of the total number of limium then i averaged it. Then repeated this for kidneyum and peagen. Then figured out there percentages. With the formula P/Wx100=%. Then i followed another formula to get the atomic mas for beanium, the formula was #1 average mass x 10% + #2 average mass x 30% + #3 average mass x 60% divided by 100. Which the answer was 0.431 g for the atomic mass for beanium. That's how I did this lab.

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